I have a problem in the 9CBS forum today.
#include
Using namespace std;
Template
Void min (const type array [size)
{COUT << Array [2];
Cout << Endl;
COUT << "The size of it: << size;
}
void main ()
{Int a [] = {1, 3, 4, 5, 6, 7, 9};
MIN (a);
}
This program has errors in VC6, because Size in MIN (a) cannot be thrown out.
This template function is min (const type array [size]), this parameter is written, but it is: const type * array. When MIN (a) is instantiated, two conversions are used in the template prunity, one is the left value conversion, one is defining modifier conversion. From int a [] à int * a à const * a. Obviously, the parameter transmission is only a pointer, which cannot know the size of the array.
There are two ways to solve:
1. Explicit template
MIN
(a);
2. Rewriting the template function declaration
1) Void min (const type * array, int size)
Institecation: MIN (a, 7);
2) Void min (& Array) [Size] // This cannot be written here, because this is not the same type with the first type of INT (a) [], which cannot be matched.
Installation: min (a)
But I found 2) Although it meets the standard (can be compiled with GCC), but cannot be compiled by VC6, there is an error:
Error C2265: '
': Reference to a Zero-Size Array Is Illegal
This is a bit of solution. More and more discovered that VC6 really doesn't comply with C standards and is a bit disappointed. But fortunately, you can compile in VC7 :)
2004-8-21
