Topic: Enter a day in a certain year, judging this day is the first day of this year?
1. Program analysis: Take March 5 as an example, you should first add the first two months, then add 5 days, the first day of this year, special
Situation, leap year and enter the month greater than 3 times more than 3 times.
2. Program source code:
Main ()
{
Int Day, Month, Year, SUM, LeAP;
Printf ("/ NPLEASE INPUT Year, Month, day / n");
Scanf ("% D,% D,% D", & Year, & Month, & Day);
Switch / * first calculate the total number of days before the month * /
{
Case 1: SUM = 0; Break;
Case 2: SUM = 31; BREAK;
Case 3: Sum = 59; Break;
Case 4: Sum = 90; Break;
Case 5: Sum = 120; Break;
Case 6: SUM = 151; BREAK;
Case 7: SUM = 181; BREAK;
Case 8: SUM = 212; Break;
Case 9: Sum = 243; Break;
Case 10: Sum = 273; Break;
Case 11: Sum = 304; Break;
Case 12: Sum = 334; Break;
Default: Printf ("Data Error"); BREAK;
}
SUM = SUM DAY; / * plus a certain day * /
IF (Year% 400 == 0 || (Year% 4 == 0 && Year% 100! = 0)) / * Judgment is a leap year * /
LEAP = 1;
Else
Leap = 0;
IF (Leap == 1 && Month> 2) / * If it is a leap year and the month is greater than 2, the total number of days should add one day * /
SUM ;
Printf ("IT IS the% DTH Day.", SUM;
