Mike Old Cat
From: the ideal of the eldest cat
This tutorial references to the C # and the ASP.NET programming tutorial, what is wrong, please point out, or in the ideal blog of the old cat.
This time a brief summary operator
Arithmetic operator
The arithmetic operator includes plus ( ), subtract (-), multiplied (*), except (/), and for removing (%). In addition to the addition or decrease of integers and real numbers, add-oriented operators is also applicable to enumeration types, string types, and commission types, which are achieved by operators.
String mf1 = "mike";
String mf2 = "cat";
String mf3 = mf1 mf2; // mf3 = "mikecat"
Using system;
ENUM Weekday
{
Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday
}
Class Mikecat
{
Static void main ()
{
Weekday mf1 = weekday.sunday;
Weekday MF2 = MF1 3;
Console.writeLine ("MF1 = {0}, MF2 = {1}", MF1, MF2);
}
} // Results: Mf1 = Sunday, MF2 = Wednesday
2. Assignment operator
Assignment is given a new value for a variable. C # middle points simple assignment and composite assignment.
Simple assignment: "=" A = b = c equivalent to a = (b = c)
Composite assignment: " =" "- =" * = "" / = "" "=" "^ =" << = ">> =" A = 10 equivalent A = a 10
3. Compare operator
The comparison operator is used to compare the size of the two expressions, such as greater than (>) <==! = <=> =.
4. Logic operator
Logic and (&&) logic or (||) and logic are not (!)
5. The bit operator is an operator that calculates the data according to the binary position. C # bit operators include bits and (&) | ~ << >>
Using system;
Class Mikecat
{
Public static void main ()
{
INT A = 6 & 3;
Console.writeLine ("a = {0}", a);
// 6 binary is the binary of 00000110, 3 is 00000011, the bit is equal to 00000010, ie 2
INT B = 6 | 3;
Console.writeline ("b = {0}", b);
// 6 binary is the binary of 00000110, 3 is 00000011, bit or after equal at 00000111, ie 7
INT C = ~ 6;
Console.writeline ("c = {0}", c);
// 6 binary is 00000110, after the reverse reverse, 11111001 is -7
INT D = 6 ^ 3;
Console.WriteLine ("D = {0}", D);
// 6 binary is the binary of 00000110, 3 is 00000011, according to or equal to 00000101, that is, 5
INT E = 6 << 3;
Console.writeline ("E = {0}", E);
// 6 binary is 00000110, left-shifting three, equal to 00101000, ie 48INT f = 6 >> 2;
Console.writeLine ("f = {0}", f);
// 6 binary is 00000110, the right shift is equal to 0000001, ie 1
}
}
6.is operator
The IS operator is used to check if the runtime object type is compatible with a given type. E is an expression in the expression "E IS T", T is a type. The return value is a Boolean value.
If the following two conditions are met, the IS expression is calculated as true value:
Expression is non-NULL.
Expression can be converted to Type. That is to say, the conversion expression of the form (type) (type) (expression) is completed without trigger an exception.
Example
// cs_keyword_is.cs
// the is operator
Using system;
Class class1
{
}
Class class2
{
}
Public Class Istest
{
Public Static Void Test (Object O)
{
Class1 a;
Class2 b;
IF (o is class1)
{
Console.writeline ("o is class1");
A = (class1) O;
// Do Something with a
}
ELSE IF (o is class2)
{
Console.WriteLine ("o is class2");
B = (Class2) O;
// Do Something with B
}
Else
{
Console.Writeline ("o is neither class1 nor class2.");
}
}
Public static void main ()
{
Class1 C1 = New class1 ();
Class2 C2 = New Class2 ();
TEST (C1);
TEST (C2);
TEST ("a string");
}
}
Output
o IS class1
o IS class2
o Is neither class1 nor class2.
7. Trimer operator
Trimed operators (? :) also known as conditional operators. For conditional expression "B? X: Y", the condition B is always calculated first, and then the judgment is performed. If the value of B is True, the value of the X is calculated, otherwise the value of Y is calculated. The conditional operator is the right operation operator, so the form of expression a? B: c? D: e calculates as follows: a? B: (c? D: e)
Operator
Point operators are used for members access. Name1. Name2
Class SIMPLE
{
Public int A;
Public void b ()
{
}
}
Simple s = new simple ();
The variable s has two members a and b; if you want to access these two members, please use the point operator
S.a = 6; // Assign to Field A;
S.B (); // invoke member function b;
So short, you have to open the publication, depressed ...
