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Title: Stack Application ---- You can perform transformation class between all values *
Description: *
Copyright: CopyRight (C) 2004 *
company: * @Author shaokun305 * @version 1.0 * /
Public class test1 {
Public Static String Changenumeric (String AASTR, INT N, INT M) {// Transform into 10
INT AA = 0; STRING RESULT = ""; stack stack = new stack (); string mmx = AASTR.TOUPPERCASE (); int endint = 0; for (int i = 0; i //System.out.println ("mid=" mid); // system.out.println ("MMX.Charat (i) =" mmx.charat (i)); int JINT = 0; Switch (MMX.Charat (i)) { Case 'a': jint = 10; Break; Case 'b': jint = 11; Break; Case 'c': jint = 12; Break; Case 'd': jint = 13; Break; Case 'E': JINT = 14; Break; Case 'f': jint = 15; Break; DEFAULT: Jint = integer.parseint ("" mmx.charat (i)); } Endint = Endint Jint * MID; //System.out.println ("Endint=" Endint); } AA = Endint; // AA now saves 10 credits // The loop is taking the rest, and the stack is performed. While (aa! = 0) { Stack.push (new integer); aa / = m; } // Sports the integer value obtained, While (! stack.isempty ()) { INT J = ((Integer) stack.pop ()). INTVALUE (); String JSTR = ""; switch (j) { Case 10: jstr = "a"; Break; Case 11: jstr = "b"; Break; Case 12: jstr = "c"; Break; Case 13: jstr = "d"; Break; Case 14: jstr = "e"; Break; Case 15: JSTR = "f"; Break; DEFAULT: JSTR = "" J; } Result = JSTR; } // Output conversion results Return Result; //system.out.println ("Result=" Result); //System.out.println (new java.util.date ());} Public test1 () {} Public static void main (string [] args) {system.out.println (new java.util.date ()); test1 testx = new test1 (); string result = "; stack stack = new stack (); if (args.lendhe> = 3) { INT AA = 0; // INTEGER.PARSEINT (Args [0]); int n = integer.parseint (args [1]); int m = integer.parseint (args [2]); / * / transformation into 10 system String mmx = args [0] .touppercase (); int endint = 0; for (int i = 0; i //System.out.println ("mid=" mid); // system.out.println ("MMX.Charat (i) =" mmx.charat (i)); int JINT = 0; switch (mmx.charat (i)) { Case 'a': jint = 10; Break; Case 'b': jint = 11; Break; Case 'c': jint = 12; Break; Case 'd': jint = 13; Break; Case 'E': JINT = 14; Break; Case 'f': jint = 15; Break; DEFAULT: Jint = integer.parseint ("" mmx.charat (i)); } Endint = Endint Jint * MID; //System.out.println ("Endint=" Endint); } AA = Endint; // AA now saves 10 credits // The loop is taking the rest, and the stack is performed. While (aa! = 0) { Stack.push (new integer); aa / = m; } // Sports the integer value obtained, While (! stack.isempty ()) { INT J = ((Integer) stack.pop ()). INTVALUE (); string jstr = ""; switch (j) {case 10: jstr = "a"; Break; Case 11: jstr = "b"; Break; Case 12: jstr = "c"; Break; Case 13: jstr = "d"; Break; Case 14: jstr = "e"; Break; Case 15: JSTR = "f"; Break; DEFAULT: JSTR = "" j;} Result = JSTR; } * / Result = TEST1.CHANGENUMERIC (Args [0], N, M); } // Output conversion results System.out.println ("Result =" result); System.out.println (new java.util.date ());}} # You compile this TEST1 class, if you use JDK, you can use Javac Test1.java and then then then: Java Test1 210145 10 16 Enter: Tue Apr 20 11:50:43 CST 2004 // Start Time Result = 334E1TUE APR 20 11 : 50: 43 CST 2004 // End Time Meaning: Transform Ten Binary 210145 to 16 Entering: 334E1 Re-Test: Java Test1 4D7A8F 16 2 Output: Tue Apr 20 11:54:44 CST 2004Result = 1001101011101010001111Tue APR 20 11 : 54: 44 CST 2004 Meaning: Transfer 16-Bao 4D7A8F into 2-based 100110101111101010001111 # Specific use stack conversion algorithm description: For example (1348) 10 = (2504) 8, the operation process is as follows N n Div 8 N MOD 8 1348 168 4 168 21 0 21 2 5 2 0 2
