First-class solution for Maunda

zhaozj2021-02-16  45

When n> 2

X ^ n y ^ n = z ^ n = y ^ n x ^ n

X ^ (2) * x ^ (N-2) x * y (n) / xz ^ (n) = 0 y ^ (2) * y ^ (n-2) y * x (n) / yz ^ (n) = 0

X = {-Y ^ (N) / x ( -) [y ^ (2N) / x ^ (2) 4 * x ^ (N-2) * z ^ (n)] ^ (1/2) ]} / {2x ^ (n-2)} .......

1 = {-Y ^ (N) / x ( -) [y ^ (2N) / x ^ (2) 4 * x ^ (N-2) * z ^ (n)] ^ (1/2) ]} / 2 * x ^ (n-3) .......

-Y ^ (n) / x ( -) [y ^ (2N) / x ^ (2) 4 * x ^ (N-2) * z ^ (n)] ^ (1/2)] - 2X ^ (n-3) = 0 .......

(1): -y ^ (n) / x-2x ^ (n-3) = 0 .......

(2): [Y ^ (2N) / x ^ (2) 4 * x ^ (N-2) * z ^ (n)] ^ (1/2)] = 0 .......

(A): y = 0 (a *): y = 0

(B): x> <0 (b *): x = 0

(C): z = 0 (c *): z = 0

(A) contradiction with (a *)

It has not been solved.

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