How to implement online users in PHP

zhaozj2021-02-17  40

$ TIME = getdate ();

$ TT = $ TIME [Year] * 365 * 24 * 60 $ TIME [MON] * 30 * 24 * 60 $ TIME [MDAY] * 24 * 60 $ TIME [Hours] * 60 $ TIME [minutes] ;

IF ($ UserID! = "Guest") {

$ SQLQQ = "Update $ user_attr_table set time = $ tt, status = 1 where userid = '$ userid'";

MySQL_QUERY ($ SQLQQ);

$ SQLQ = "SELECT STATUS, UserId, Time from $ User_attr_table where status = 1;"

$ resultq = mysql_query ($ sqlq) or Die (MySQL_ERROR ());

$ countq = mysql_numrows ($ resultQ);

For ($ II = 0; $ II <$ COUNTQ; $ II ) {

$ rowq = mysql_fetch_Array ($ results);

$ useridq = $ rowq [userid];

$ TIMES = $ ROWQ [TIME];

$ TS = $ TT- $ TIMES;

IF ($ TS> = 15)

{

$ SQLS = "Update $ user_attr_table set status = 0 where userid = '$ useridq'"

MySQL_Query ($ SQLS);

}

}

?>

I wrote the code down, and I will see your own :)

If you don't understand, you can ask questions.

I am often here :)

转载请注明原文地址:https://www.9cbs.com/read-30937.html

New Post(0)