Poverty algorithm

xiaoxiao2021-03-05  23

#include using namespace std; #include

INT main () {long ar [3]; // password dictionary subscript const INT f = 6; // password dictionary length INT i; for (i = 0; i <3; i ) ar [i] = 0; Bool BNEXT; BNEXT = true; while (bnext) {

Printf ("% D-% D-% D / T", Ar [2], Ar [1], Ar [0]); for (i = 0; i <3; i ) {Ar [i] ; If (ar [i]! = F) {Break;} else {ar [i] = 0; if (i == 2) bnext = false;}}}}

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