If a small cow begins with one cow from birth every four years, how many cows are in the nth year of this law. (Refer to C programming money)
Source: This is the first program that I have just written when I have a big two (2001). ^ _ ^.
(1): Texture within 20 years
#include
void main ()
{
Long Int A [20] [3];
INT I, J, N;
a [0] [0] = 1;
a [0] [1] = 1;
a [0] [2] = 1;
For (i = 1; i <20; i )
{
A [I] [1] = a [i-1] [0] a [i-1] [1] a [i-1] [2];
a [i] [0] = a [i] [1] -a [i-1] [1];
A [i] [2] = a [i] [1] a [i-1] [2];
}
CIN >> N;
IF (n% 3 == 0)
J = 2;
IF (n% 3 == 1)
J = 0;
IF (n% 3 == 2)
J = 1;
I = (N-1-J) / 3;
COUT << "" "" << "Year of the Year" << Endl;
COUT << a [i] [j] << endl;
}
(2) Recursive algorithm
#include
Long Int Cow (int);
void main ()
{
Int n;
Long Int Y;
COUT << "Input a integer number" << Endl;
CIN >> N;
Y = COW (n);
COUT << n << "" << Y << Endl;
}
Long int COW (INT N)
{
Long Int F;
IF (n <= 3)
Return 1;
Else
Return (COW (N-1) COW (N-3));
}
