Example 3. Please prepare a functionality of FUN (), which is:
S = 1 / (1 × 2) 1 / (2 × 3) ... 1 / (N × (n 1)))
For example: if n = 10, the S value is 0.909091.
Question procedure: (Similar Example 2)
#include
#include
#include
Double Fun (int N)
{
}
Main ()
{
Int n;
Double S;
CLRSCR ();
Printf ("/ N / NINPUT N:");
Scanf ("% d", & n);
S = Fun (n);
Printf ("/ N / NTHE S =% f / n / n", s);
}
Reference answer: (Note there is an error)
Double Fun (int N)
{
INT I;
Double S = 0.0, T = 0.0;
For (i = 1; i <= n; i )
{
/ *** there is a error in here *** /
T = 1 / (i * (i 1));
/ *********** * End ************** /
S = T;
}
Return S;
}
Example 4. Please prepare a functionality of FUN (), which is:
S = 1 x x2 / 2! x3 / 3! ... XN / N!
For example: if n = 10; x = 0.3, the S value is 1.349859.
Question procedure:
#include
#include
#include
Double Fun (Double X, INT N)
{
}
Main ()
{
Int n;
Double X, S;
CLRSCR ();
Printf ("/ N / NINPUT N:");
Scanf ("% d", & n);
Printf ("/ n / ninput x:");
Scanf ("% lf", & x);
s = fun (x, n);
Printf ("/ N / NTHE S =% f / n / n", s);
}
Reference answer:
Double Fun (Double X, INT N)
{
INT I, J, T = 1;
Double S = 0.0, P = 0.0;
For (i = 1; i <= n; i )
{
T = 1; for (j = 1; j <= i; j ) {t = T * j;} / * equivalent to t * = i; * /
P = p * t;
S = S P / T;
}
Return S;
}
There is also a remember X0.5 = √X (the square of X).
