/ *
* Create Date 2005-3-8
*
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* /
Package com.test;
/ **
* @Author administrator
*
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* /
Public class testRMB {
/ **
* Test NumberConvert method
* @Param args string []
* /
Public static void main (String [] args) {
// This is the largest number that can be converted
String RMB = "90909.99";
System.out.Println (NumberConvert (RMB));
}
/ **
* Translate the character string into Chinese.
* @Param IN number
* @Return Chinese capital
* /
Public Static String NumberConvert (String in) {
StringBuffer out = new stringbuffer ();
String chn [] = {
"Zero", "", "", "", "", "Wu", "Lu", "柒", "捌", "玖"}
String end [] = {
"" "" "," "," 仟 ",}
String mid [] = {
"" "万", "hundred million", "mega",}
Double Ind = double.parsedouble (in);
Long Ind_Left = (long) indifer
Long [] INTE = new long [13]; // Store integer bit
int [] floa = new int [4]; // Store a small number
/ * Put an integer part into intee [] * /
For (int i = 12; I> = 0; I -) {
INTE [I] = (long) (Math.Pow (10, I)));
Ind_Left% = (long) (Math.Pow (10, i));
}
/ * 小 部分 部分 部分 部分 部分入 [] * /
Int index = in.indexof ('.');
IF (INDEX! = -1) {
String str = in.substring (Index 1);
For (int i = 0; i Floa [I] = integer.parseint (Str.Substring (i, i 1)); } } / ** If the integer bit is not 0, handle an integer example: 111.1234 ** / IF ((int) ind! = 0) { INT i = 12; While (INTE [I] == 0) {file: // Find the first place I-; } / * Output to OUT * / For (int J = I / 4; J> = 0; J -) { IF (j == 3) {// If the number is 13 bits, handle 1 megabo OUT.APpend (INTE [12])]). Append (MID [3]); J -; } For (int K = 3; k> = 0; k -) { INT NUM = 4 * J K; IF (INTE [NUM]! = 0) {// No 0 to add 10,000 OUT.APPEND (CHN [NUM])]). Append (end [k]); } Else { IF (k == 0 || K == 0 && k == 1 || K == 0 && k == 1 && k == 2 || K == 0 && k == 1 && k == 2 && k == 3) {} // If it is the last few of the trillion, it is not output. Else { IF (INTE [NUM - 1] == 0) {} // According to the latter, it is not 0 to determine the addition of 0 examples: 1003 Else { Out.append (chn [0]); } } } } IF (! (INTE [J * 4 0] == 0 && INTE [J * 4 1] == 0 && INTE [J * 4 2] == 0 && INTE [J * 4 3] == 0)) {// If there is a full 0 or no output position example: 1000 0000 0003 will not appear one hundred billion Ten only OUT.APPEND (MID [J]); } } IF (out.charat (0) == 'zero') {// Because the last one does not have the next bit, it is 0 to delete it. Out.deleteCharat (0); } // Example 30 } / ** If the integer bit is 0, the integer bit is processed, plus 0 examples: 0.1234 ** / Else { Out.Append ('zero'); } / * Processing the decimal part * / / * If there is a small number * / IF (INDEX! = -1) { Out.Append ('point'); // Handling a decimal place For (int m = 0; m <= 3; m ) { Out.append (chn [floa [m]]); } INT ZERO = OUT.LENGTH () - 1; While (out.charat (zero) == 'zero') {// The last few bits are 0, then delete Out.deletecharat (zero); ZERO ---; } } Return out.toString (); } }
