View the statement of retrama

xiaoxiao2021-03-06  37

Break ON AddressColumn Address Noprint

Select A.address, Executions, B.SQL_TextFrom V $ SQLAREA A, V $ SQLText Bwhere Parse_Calls! = 1and Parse_Calls = Executionsand A.Address = B.AddressOrder by Executions, A.Address, B.Piece;

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