Take another rule

zhaozj2021-02-16  183

Except for rule 2 Occasion 3 All digits (DIGITS) total 3 multiples 4 Maximum number of two digits 5 Maximum number 5 The last digit is 0 or 56 can be used at 2 and 3 to remove 7take the last digit, Double IT And Subtract it from the rest of the number; if the answer is divisible by 7 (including 0), The Number IS Also. 8 The last 3 digits can be 8 all the number of 9 all digits of 9 multiples 10 The last digit is the fact that 011 odd number of bits and even bits of even bits are 11 multiples 12 simultaneous 3 and 4, 13delete the last digit from the number, the subtract 9 Times the deleted Digit from the remaining number . If what is left is divisible by 13, then is the original number.

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